1991 AMC 8 Problem 3
Attempt Problem 3 of the 1991 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1991 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
3.
Two hundred thousand times two hundred thousand equals
four hundred thousand
four million
forty thousand
four hundred million
forty billion
Answer: E
Small hint:
Write two hundred thousand as
Big hint:
Multiply the leading digits, then count the zeros: each factor has five zeros
Solution:
which is forty billion.
Thus, the correct answer is E .
Problem 3 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
- 1995 AMC 8
- 1996 AMC 8
- 1997 AMC 8
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- 1999 AMC 8
- 2000 AMC 8
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