1990 AMC 8 Problem 14
Attempt Problem 14 of the 1990 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1990 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
14.
A bag contains only blue balls and green balls. There are blue balls. If the probability of drawing a blue ball at random from this bag is then the number of green balls in the bag is
Answer: B
Small hint:
If the probability of blue is then blue balls are a quarter of the total
Big hint:
Use blue balls to find the total, then subtract to get the green balls
Solution:
Since blue balls make up of the bag and there are of them, the total is balls.
So the number of green balls is .
Thus, the correct answer is B .
Problem 14 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
- 1994 AMC 8
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