1986 AMC 8 Problem 23

Attempt Problem 23 of the 1986 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1986 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

The large circle has diameter AC.AC. The two small circles have their centers on ACAC and just touch at O,O, the center of the large circle. If each small circle has radius 1,1, what is the value of the ratio of the area of the shaded region to the area of one of the small circles?
between 12\dfrac12 and 11
11
between 11 and 32\dfrac32
between 32\dfrac32 and 22
cannot be determined from the information given
Answer: B
Concepts:circle areaarea decomposition
Small hint:
The large circle has radius 2,2, since ACAC equals two small diameters
Big hint:
By symmetry the shaded region is half the difference between the large circle’s area and the two small circles’ area
Solution:
The large circle has radius 2,2, so its area is π(2)2=4π,\pi(2)^2 = 4\pi, and each small circle has area π.\pi.
By symmetry the shaded region is half the difference of the areas: 12(4π−2π)=π.\dfrac12(4\pi - 2\pi) = \pi. The ratio of this to one small circle’s area π\pi is 1.1.
Thus, the correct answer is B .
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