2021 AMC 12A Spring Problem 3

Attempt Problem 3 of the 2021 AMC 12A Spring below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12A Spring solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

The sum of two natural numbers is 17,402.17{,}402. One of the two numbers is divisible by 10.10. If the units digit of that number is erased, the other number is obtained. What is the difference of these two numbers?
10,27210{,}272
11,70011{,}700
13,36213{,}362
14,23814{,}238
15,42615{,}426
Answer: D
Concepts:place valuelinear equation
Small hint:
Erasing the units digit 00 of a multiple of 1010 divides it by 1010
Big hint:
If the smaller number is x,x, the larger is 10x,10x, so 11x=17,40211x = 17{,}402
Solution:
The larger number ends in 0,0, and erasing that digit divides it by 1010 to give the smaller number. So the larger number is 1010 times the smaller. Writing the smaller number as x,x, the sum is x+10x=11x=17,402,x + 10x = 11x = 17{,}402, giving x=1,582.x = 1{,}582.
The two numbers are 1,5821{,}582 and 15,820,15{,}820, whose difference is 15,820−1,582=14,238.15{,}820 - 1{,}582 = 14{,}238.
Thus, the correct answer is D.
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