2020 AMC 12B Problem 2

Attempt Problem 2 of the 2020 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

What is the value of the following expression?
1002−72702−112⋅(70−11)(70+11)(100−7)(100+7)\frac{100^2 - 7^2}{70^2 - 11^2} \cdot \frac{(70 - 11)(70 + 11)}{(100 - 7)(100 + 7)}
11
99519950\dfrac{9951}{9950}
47804779\dfrac{4780}{4779}
108107\dfrac{108}{107}
8180\dfrac{81}{80}
Answer: A
Concepts:difference of squares
Small hint:
a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b)
Big hint:
Factor 1002−72100^2 - 7^2 and 702−11270^2 - 11^2, then look for cancellation
Solution:
Using the difference of squares, 1002−72=(100−7)(100+7)100^2 - 7^2 = (100 - 7)(100 + 7) and 702−112=(70−11)(70+11).70^2 - 11^2 = (70 - 11)(70 + 11). The expression becomes (100−7)(100+7)(70−11)(70+11)⋅(70−11)(70+11)(100−7)(100+7)=1. \begin{aligned} &\frac{(100 - 7)(100 + 7)}{(70 - 11)(70 + 11)} \\ &\quad {}\cdot \frac{(70 - 11)(70 + 11)}{(100 - 7)(100 + 7)} = 1. \end{aligned}
Thus, the correct answer is A.
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