2018 AMC 12A Problem 21

Attempt Problem 21 of the 2018 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 12A solutions, or check the answer key.

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21.

Which of the following polynomials has the greatest real root?

x19+2018x11+1x^{19} + 2018x^{11} + 1

x17+2018x11+1x^{17} + 2018x^{11} + 1

x19+2018x13+1x^{19} + 2018x^{13} + 1

x17+2018x13+1x^{17} + 2018x^{13} + 1

2019x+20182019x + 2018

Answer: B
Concepts:polynomialinequalitybounding to limit cases
Difficulty rating: 2210
Solution:

Each polynomial in choices A–D has no positive root and exactly one negative root, which lies in (1,0)(-1, 0) (it is positive at 00 and negative at 1-1) and is increasing there. On the interval (1,0),(-1, 0), x19>x17x^{19} \gt x^{17} and x13>x11.x^{13} \gt x^{11}. Thus each of A, C, and D has a larger value than B at every point of this interval, so each crosses 00 to the left of B. Therefore B has the greatest root among A–D.

The linear choice E has root e=20182019.e=-\tfrac{2018}{2019}. Since 20182019>910,\tfrac{2018}{2019}\gt\tfrac9{10}, we have e17+2018e11+1e^{17}+2018e^{11}+1 <2018(910)11+1\lt-2018\left(\tfrac9{10}\right)^{11}+1 <0.\lt0. Because B is increasing and is negative at e,e, its root lies to the right of E's. Hence B has the greatest real root.

Thus, the correct answer is B.

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