2017 AMC 12B Problem 5

Attempt Problem 5 of the 2017 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

The data set [6,19,33,33,39,[6, 19, 33, 33, 39, 41,41, 41,41, 43,43, 51,51, 57]57] has median Q2=40,Q_2 = 40, first quartile Q1=33,Q_1 = 33, and third quartile Q3=43.Q_3 = 43. An outlier in a data set is a value that is more than 1.51.5 times the interquartile range below the first quartile (Q1)(Q_1) or more than 1.51.5 times the interquartile range above the third quartile (Q3),(Q_3), where the interquartile range is defined as Q3−Q1.Q_3 - Q_1. How many outliers does this data set have?
00
11
22
33
44
Answer: B
Concepts:median (data)
Small hint:
The interquartile range is Q3−Q1=43−33=10Q_3 - Q_1 = 43 - 33 = 10
Big hint:
Count values below 33−1.5(10)33 - 1.5(10) or above 43+1.5(10)43 + 1.5(10)
Solution:
The interquartile range is 43−33=10,43 - 33 = 10, so 1.51.5 times it is 15.15. Outliers are values less than 33−15=1833 - 15 = 18 or greater than 43+15=58.43 + 15 = 58. Only 66 falls below 18,18, and nothing exceeds 58,58, so there is exactly 11 outlier.
Thus, the correct answer is B.
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