2017 AMC 12A Problem 17

Attempt Problem 17 of the 2017 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

17.

There are 2424 different complex numbers zz such that z24=1.z^{24}=1. For how many of these is z6z^6 a real number?
00
44
66
1212
2424
Answer: D
Concepts:roots of unitycomplex number
Small hint:
Write z=eπik12z=e^{\frac{\pi i k}{12}} for k=0,1,…,23k=0,1,\ldots,23
Big hint:
Then z6=eπik2,z^6=e^{\frac{\pi i k}{2}}, which is real exactly when kk is even
Solution:
The 2424 solutions are the 2424th roots of unity, z=eπik12z=e^{\frac{\pi i k}{12}} for k=0,1,…,23.k=0,1,\ldots,23.
Then z6=eπik2=cos⁡kπ2+isin⁡kπ2,z^6=e^{\frac{\pi i k}{2}}=\cos\dfrac{k\pi}{2}+i\sin\dfrac{k\pi}{2}, which is real exactly when sin⁡kπ2=0,\sin\dfrac{k\pi}{2}=0, i.e. when kk is even. There are 1212 even values of kk in the range.
Thus, the correct answer is D.
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