2016 AMC 12A Problem 8

Attempt Problem 8 of the 2016 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 12A solutions, or check the answer key.

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8.

What is the area of the shaded region of the given 8×58\times 5 rectangle?

4344\tfrac{3}{4}

55

5145\tfrac{1}{4}

6126\tfrac{1}{2}

88

Answer: D
Concepts:triangle areasymmetry
Difficulty rating: 1350
Solution:

The diagonal of the rectangle from the upper-left corner to the lower-right corner divides the shaded region into four triangles, all meeting at the center of the rectangle.

Two of these triangles have a horizontal base of length 11 and altitude 125=52,\frac12\cdot 5=\frac52, and the other two have a vertical base of length 11 and altitude 128=4.\frac12\cdot 8=4. The total area is 212152+21214=52+4=132. \begin{gathered} 2\cdot\dfrac12\cdot 1\cdot\dfrac52\\ {}+2\cdot\dfrac12\cdot 1\cdot 4\\ =\dfrac52+4\\ =\dfrac{13}{2}. \end{gathered}

Thus, the correct answer is D.

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