2016 AMC 12A Problem 8

Attempt Problem 8 of the 2016 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

What is the area of the shaded region of the given 8×58\times 5 rectangle?
4344\tfrac{3}{4}
55
5145\tfrac{1}{4}
6126\tfrac{1}{2}
88
Answer: D
Concepts:triangle areasymmetry
Small hint:
Every drawn segment passes through the center of the rectangle
Big hint:
The main diagonal splits the shaded region into four triangles, each with base 11
Solution:
The diagonal of the rectangle from the upper-left corner to the lower-right corner divides the shaded region into four triangles, all meeting at the center of the rectangle.
Two of these triangles have a horizontal base of length 11 and altitude 12⋅5=52,\frac12\cdot 5=\frac52, and the other two have a vertical base of length 11 and altitude 12⋅8=4.\frac12\cdot 8=4. The total area is 2⋅12⋅1⋅52+2⋅12⋅1⋅4=52+4=132. \begin{gathered} 2\cdot\dfrac12\cdot 1\cdot\dfrac52\\ {}+2\cdot\dfrac12\cdot 1\cdot 4\\ =\dfrac52+4\\ =\dfrac{13}{2}. \end{gathered}
Thus, the correct answer is D.
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