2016 AMC 12A Problem 2

Attempt Problem 2 of the 2016 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

For what value of xx does 10x⋅1002x=10005?10^x\cdot 100^{2x}=1000^5?
11
22
33
44
55
Answer: C
Concepts:exponent
Small hint:
Write every base as a power of 1010
Big hint:
The left side becomes 105x10^{5x} and the right side 101510^{15}
Solution:
Since 100=102100=10^2 and 1000=103,1000=10^3, the equation becomes 10x⋅104x=1015, 10^x\cdot 10^{4x}=10^{15}, so 105x=1015.10^{5x}=10^{15}. Then 5x=15,5x=15, giving x=3.x=3.
Thus, the correct answer is C.
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