2015 AMC 12B Problem 3

Attempt Problem 3 of the 2015 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 12B solutions, or check the answer key.

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3.

Isaac has written down one integer two times and another integer three times. The sum of the five numbers is 100,100, and one of the numbers is 28.28. What is the other number?

88

1111

1414

1515

1818

Answer: A
Concepts:Diophantine Equationdivisibility
Difficulty rating: 1050
Solution:

Write 2x+3y=100.2x + 3y = 100. If 2828 were written twice, then 3y=10056=44,3y = 100 - 56 = 44, which is not a multiple of 3.3.

So 2828 is written three times: 2x=10084=16,2x = 100 - 84 = 16, giving x=8.x = 8.

Thus, the correct answer is A.

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