2015 AMC 12B Problem 3

Attempt Problem 3 of the 2015 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

Isaac has written down one integer two times and another integer three times. The sum of the five numbers is 100,100, and one of the numbers is 28.28. What is the other number?
88
1111
1414
1515
1818
Answer: A
Concepts:Diophantine Equationdivisibility
Small hint:
Let xx appear twice and yy appear three times, so 2x+3y=1002x + 3y = 100
Big hint:
Test whether 2828 is the number written two times or three times, and keep the integer case
Solution:
Write 2x+3y=100.2x + 3y = 100. If 2828 were written twice, then 3y=100−56=44,3y = 100 - 56 = 44, which is not a multiple of 3.3.
So 2828 is written three times: 2x=100−84=16,2x = 100 - 84 = 16, giving x=8.x = 8.
Thus, the correct answer is A.
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