2015 AMC 12A Problem 2

Attempt Problem 2 of the 2015 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

Two of the three sides of a triangle are 2020 and 15.15. Which of the following numbers is not a possible perimeter of the triangle?
5252
5757
6262
6767
7272
Answer: E
Concepts:triangle inequalitybounding to limit cases
Small hint:
The third side lies strictly between 20−1520-15 and 20+1520+15
Big hint:
Add 20+1520+15 to that range to bound the perimeter
Solution:
By the Triangle Inequality, the third side ss satisfies 20−15<s<20+15,20-15 \lt s \lt 20+15, that is 5<s<35.5 \lt s \lt 35.
The perimeter is 35+s,35 + s, so it lies strictly between 4040 and 70.70. Among the choices, only 7272 falls outside this range.
Thus, the correct answer is E.
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