2014 AMC 12A Problem 5

Attempt Problem 5 of the 2014 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

On an algebra quiz, 10%10\% of the students scored 7070 points, 35%35\% scored 8080 points, 30%30\% scored 9090 points, and the rest scored 100100 points. What is the difference between the mean and the median of the students’ scores on this quiz?
11
22
33
44
55
Answer: C
Concepts:meanmedian (data)percentage
Small hint:
The median is the score of the middle student after ordering everyone
Big hint:
Compute the weighted mean 0.10(70)+0.35(80)0.10(70)+0.35(80) +0.30(90)+0.25(100)+0.30(90)+0.25(100) and compare it to the median
Solution:
The remaining 25%25\% scored 100.100. Since 45%45\% scored at most 8080 and 75%75\% scored at most 90,90, the median is 90.90.
The mean is 0.10(70)+0.35(80)+0.30(90)+0.25(100)=7+28+27+25=87. \begin{aligned} &0.10(70)+0.35(80)\\ &\quad{}+0.30(90)+0.25(100)\\ &\quad{}=7+28+27+25=87. \end{aligned}
The difference is 90−87=3.90-87=3.
Thus, the correct answer is C.
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