2013 AMC 12B Problem 14

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14.

Two non-decreasing sequences of nonnegative integers have different first terms. Each sequence has the property that each term beginning with the third is the sum of the previous two terms, and the seventh term of each sequence is N.N. What is the smallest possible value of N?N?

5555

8989

104104

144144

273273

Answer: C
Concepts:FibonacciDiophantine Equationgreatest common divisor
Difficulty rating: 1750
Solution:

A sequence starting a1,a2a_1, a_2 has seventh term 5a1+8a2.5a_1 + 8a_2. For the two sequences, 5a1+8a2=5b1+8b2,5a_1 + 8a_2 = 5b_1 + 8b_2, so 5(b1a1)=8(a2b2).5(b_1 - a_1) = 8(a_2 - b_2). Since gcd(5,8)=1,\gcd(5, 8) = 1, we need 8b1a18 \mid b_1 - a_1 and 5a2b2.5 \mid a_2 - b_2. Taking a1<b1a_1 \lt b_1 with nondecreasing terms gives a1b18b28a213.a_1 \le b_1 - 8 \le b_2 - 8 \le a_2 - 13. Choosing a1=0,a_1 = 0, b1=b2=8,b_1 = b_2 = 8, a2=13a_2 = 13 yields N=50+813=104.N = 5\cdot 0 + 8\cdot 13 = 104. Thus, the correct answer is C.

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