2012 AMC 12B Problem 2

Attempt Problem 2 of the 2012 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

A circle of radius 55 is inscribed in a rectangle as shown. The ratio of the length of the rectangle to its width is 2:1.2:1. What is the area of the rectangle?
5050
100100
125125
150150
200200
Answer: E
Concepts:circlerectangle
Small hint:
The width of the rectangle equals the diameter of the circle
Big hint:
The length is twice the width
Solution:
The circle is inscribed, so the width of the rectangle equals the diameter, 2⋅5=10.2\cdot5=10.
The length is then 2⋅10=20,2\cdot10=20, so the area is 10⋅20=200.10\cdot20=200.
Thus, the correct answer is E.
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