2011 AMC 12B Problem 2

Attempt Problem 2 of the 2011 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

Josanna’s test scores to date are 90,90, 80,80, 70,70, 60,60, and 85.85. Her goal is to raise her test average at least 33 points with her next test. What is the minimum test score she would need to accomplish this goal?
8080
8282
8585
9090
9595
Answer: E
Concepts:mean
Small hint:
Find the current average of the five scores
Big hint:
The six scores must total 66 times the target average
Solution:
The five scores sum to 90+80+70+60+85=385,90+80+70+60+85=385, giving an average of 77.77. The goal is a new average of at least 80.80.
Six tests averaging 8080 must total 6⋅80=480,6\cdot80=480, so the sixth score must be at least 480−385=95.480-385=95.
Thus, the correct answer is E.
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