2009 AMC 12A Problem 17

Attempt Problem 17 of the 2009 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

17.

Let a+ar1+ar12+ar13+⋯a + ar_1 + ar_1^2 + ar_1^3 + \cdots and a+ar2+ar22+ar23+⋯a + ar_2 + ar_2^2 + ar_2^3 + \cdots be two different infinite geometric series of positive numbers with the same first term. The sum of the first series is r1,r_1, and the sum of the second series is r2.r_2. What is r1+r2?r_1 + r_2?
00
12\dfrac{1}{2}
11
1+52\dfrac{1 + \sqrt{5}}{2}
22
Answer: C
Concepts:geometric sequenceVieta’s Formulas
Small hint:
The sum of an infinite geometric series with first term aa and ratio rr is a1−r\dfrac{a}{1 - r}
Big hint:
Each ratio satisfies a1−r=r,\dfrac{a}{1 - r} = r, that is r2−r+a=0;r^2 - r + a = 0; use Vieta on the two roots
Solution:
For a series with first term aa and ratio r,r, the sum is a1−r=r,\dfrac{a}{1 - r} = r, so r2−r+a=0.r^2 - r + a = 0.
Both r1r_1 and r2r_2 satisfy this same quadratic, and since the two series are different, r1≠r2,r_1 \ne r_2, so they are its two distinct roots. By Vieta’s formulas, r1+r2=1.r_1 + r_2 = 1.
Thus, the correct answer is C.
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