2008 AMC 12A Problem 2

Attempt Problem 2 of the 2008 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 12A solutions, or check the answer key.

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2.

What is the reciprocal of 12+23?\dfrac{1}{2} + \dfrac{2}{3}?

67\dfrac{6}{7}

76\dfrac{7}{6}

53\dfrac{5}{3}

33

72\dfrac{7}{2}

Answer: A
Concepts:fraction
Difficulty rating: 910
Solution:

Using a common denominator, 12+23=36+46=76. \dfrac{1}{2} + \dfrac{2}{3} = \dfrac{3}{6} + \dfrac{4}{6} = \dfrac{7}{6}.

The reciprocal of 76\dfrac{7}{6} is 67.\dfrac{6}{7}.

Thus, A is the correct answer.

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