2007 AMC 12B Problem 7

Attempt Problem 7 of the 2007 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

All sides of the convex pentagon ABCDEABCDE are of equal length, and ∠A=∠B=90∘.\angle A=\angle B=90^\circ. What is the degree measure of ∠E?\angle E?
9090
108108
120120
144144
150150
Answer: E
Concepts:equilateral trianglesquare (geometry)angle sum
Small hint:
The sides AB,BC,EAAB,BC,EA and the two right angles make ABCEABCE a square
Big hint:
Then △CDE\triangle CDE is equilateral, and ∠E=∠AEC+∠CED\angle E=\angle AEC+\angle CED
Solution:
Because AB=BC=EAAB=BC=EA and ∠A=∠B=90∘,\angle A=\angle B=90^\circ, quadrilateral ABCEABCE is a square, so ∠AEC=90∘\angle AEC=90^\circ and ECEC equals the common side length.
Then CD=DE=EC,CD=DE=EC, so △CDE\triangle CDE is equilateral and ∠CED=60∘.\angle CED=60^\circ. Therefore ∠E=∠AEC+∠CED=90∘+60∘=150∘. \begin{aligned} \angle E&=\angle AEC+\angle CED \\ &=90^\circ+60^\circ \\ &=150^\circ. \end{aligned}
Thus, the correct answer is E.
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