2007 AMC 12B Problem 7

Attempt Problem 7 of the 2007 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 12B solutions, or check the answer key.

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7.

All sides of the convex pentagon ABCDEABCDE are of equal length, and A=B=90.\angle A=\angle B=90^\circ. What is the degree measure of E?\angle E?

9090

108108

120120

144144

150150

Answer: E
Concepts:equilateral trianglesquare (geometry)angle sum
Difficulty rating: 1330
Solution:

Because AB=BC=EAAB=BC=EA and A=B=90,\angle A=\angle B=90^\circ, quadrilateral ABCEABCE is a square, so AEC=90\angle AEC=90^\circ and ECEC equals the common side length.

Then CD=DE=EC,CD=DE=EC, so CDE\triangle CDE is equilateral and CED=60.\angle CED=60^\circ. Therefore E=AEC+CED=90+60=150. \begin{aligned} \angle E&=\angle AEC+\angle CED \\ &=90^\circ+60^\circ \\ &=150^\circ. \end{aligned}

Thus, the correct answer is E.

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