2004 AMC 12A Problem 2

Attempt Problem 2 of the 2004 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

On the AMC 12,12, each correct answer is worth 66 points, each incorrect answer is worth 00 points, and each problem left unanswered is worth 2.52.5 points. If Charlyn leaves 88 of the 2525 problems unanswered, how many of the remaining problems must she answer correctly in order to score at least 100?100?
1111
1313
1414
1616
1717
Answer: C
Concepts:inequalityfloor and ceiling functions
Small hint:
The 88 blanks already contribute 2.5×82.5 \times 8 points
Big hint:
Find the smallest number of correct answers whose 66 points each cover the remaining points
Solution:
The 88 unanswered problems are worth 2.5×8=202.5 \times 8 = 20 points, so Charlyn needs at least 100−20=80100 - 20 = 80 more points from correct answers.
Each correct answer is worth 66 points, and the smallest multiple of 66 that is at least 8080 is 84=6×14.84 = 6 \times 14. So she needs at least 1414 correct answers.
Thus, the correct answer is C.
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