2003 AMC 12B Problem 2

Attempt Problem 2 of the 2003 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

Al gets the disease algebritis and must take one green pill and one pink pill each day for two weeks. A green pill costs $1\$1 more than a pink pill, and Al’s pills cost a total of $546\$546 for the two weeks. How much does one green pill cost?
$7\$7
$14\$14
$19\$19
$20\$20
$39\$39
Answer: D
Concepts:system of equationslinear equation
Small hint:
Two weeks is 1414 days, so find the cost of one day’s pair of pills first
Big hint:
If a green pill costs g,g, then the pink pill costs g−1,g - 1, and g+(g−1)g + (g-1) is one day’s cost
Solution:
Over 1414 days the daily cost of the two pills is 54614=39. \frac{546}{14} = 39.
Let gg be the cost of a green pill. The pink pill costs g−1,g - 1, so g+(g−1)=39, g + (g - 1) = 39, giving g=20.g = 20.
Thus, the correct answer is D.
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