2002 AMC 12B Problem 5

Attempt Problem 5 of the 2002 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 12B solutions, or check the answer key.

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5.

Let v,v, w,w, x,x, y,y, and zz be the degree measures of the five angles of a pentagon. Suppose v<w<x<y<zv\lt w\lt x\lt y\lt z and v,v, w,w, x,x, y,y, zz form an arithmetic sequence. Find the value of x.x.

7272

8484

9090

108108

120120

Answer: D
Concepts:angle sumarithmetic sequence
Difficulty rating: 1080
Solution:

The five interior angles sum to 540.540^\circ. Writing the sequence as x2d,x-2d, xd,x-d, x,x, x+d,x+d, x+2d,x+2d, the sum is 5x=540,5x=540, so x=108.x=108.

Thus, the correct answer is D.

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