2002 AMC 12A Problem 25

Attempt Problem 25 of the 2002 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 12A solutions, or check the answer key.

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25.

The nonzero coefficients of a polynomial PP with real coefficients are all replaced by their mean to form a polynomial Q.Q. Which of the following could be a graph of y=P(x)y = P(x) and y=Q(x)y = Q(x) over the interval −4≤x≤4?-4 \le x \le 4?
Answer: B
Concepts:polynomialdata and graph interpretation
Small hint:
The sum of the coefficients of PP equals the sum of the coefficients of QQ
Big hint:
Evaluating at x=1x = 1 gives P(1)=Q(1),P(1) = Q(1), so the two graphs must intersect at x=1x = 1
Solution:
Replacing the nonzero coefficients by their mean keeps the total of the coefficients unchanged, so PP and QQ have the same coefficient sum. Since P(1)P(1) and Q(1)Q(1) each equal that sum, P(1)=Q(1).P(1) = Q(1).
Therefore the graphs of y=P(x)y = P(x) and y=Q(x)y = Q(x) must cross at x=1.x = 1. The only choice showing an intersection at x=1x = 1 is graph B. (There, P(x)=2x4−3x2−3x−4P(x) = 2x^4 - 3x^2 - 3x - 4 and Q(x)=−2x4−2x2−2x−2.Q(x) = -2x^4 - 2x^2 - 2x - 2.)
Thus, the correct answer is B.
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