2000 AMC 12 Problem 8

Attempt Problem 8 of the 2000 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 12 solutions, or check the answer key.

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8.

Figures 0,1,2,0, 1, 2, and 33 consist of 1,5,13,1, 5, 13, and 2525 nonoverlapping unit squares, respectively. If the pattern were continued, how many nonoverlapping unit squares would there be in figure 100?100?

1040110401

1980119801

2020120201

3980139801

4080140801

Answer: C
Concepts:pattern recognitionperfect square
Difficulty rating: 1370
Solution:

Figure nn is a diamond whose row lengths increase through the odd numbers and back down, giving a total of n2+(n+1)2n^2 + (n + 1)^2 unit squares. This matches 1,5,13,251, 5, 13, 25 for n=0,1,2,3.n = 0, 1, 2, 3.

Therefore figure 100100 has 1002+1012=10000+10201=20201 \begin{aligned} 100^2 + 101^2 &= 10000 + 10201 \\ &= 20201 \end{aligned} unit squares.

Thus, the correct answer is C.

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