2000 AMC 12 Problem 22

Attempt Problem 22 of the 2000 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 12 solutions, or check the answer key.

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22.

The graph below shows a portion of the curve defined by the quartic polynomial P(x)=x4+ax3+bx2+cx+d.P(x) = x^4 + ax^3 + bx^2 + cx + d. Which of the following is the smallest?

P(1)P(-1)

The product of the zeros of PP

The product of the non-real zeros of PP

The sum of the coefficients of PP

The sum of the real zeros of PP

Answer: C
Concepts:polynomialVieta’s Formulascomplex number
Difficulty rating: 2030
Solution:

The graph crosses the xx-axis exactly twice, both times at positive values, so PP has two real zeros and two non-real (complex conjugate) zeros.

Reading off the graph: the sum of the coefficients is P(1)>3;P(1) \gt 3; P(1)>4;P(-1) \gt 4; the sum of the real zeros is greater than 4.5;4.5; and the product of all zeros is d,d, the yy-intercept, which is less than 6.6.

Let RR be the product of the real zeros, so R>4.5.R \gt 4.5. The product of the non-real zeros is dR,\dfrac dR, which is less than 64.5<2.\dfrac{6}{4.5} \lt 2.

This is smaller than every other listed quantity.

Thus, the correct answer is C.

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