1997 AMC 12 Problem 22

Attempt Problem 22 of the 1997 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1997 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

Ashley, Betty, Carlos, Dick, and Elgin went shopping. Each had a whole number of dollars to spend, and together they had $56.\$56. The absolute difference between the amounts Ashley and Betty had to spend was $19.\$19. The absolute difference between the amounts Betty and Carlos had was $7,\$7, between Carlos and Dick was $5,\$5, between Dick and Elgin was $4,\$4, and between Elgin and Ashley was $11.\$11. How much did Elgin have?
$6\$6
$7\$7
$8\$8
$9\$9
$10\$10
Answer: E
Concepts:absolute differencessigned cases
Small hint:
Assign a sign to each successive difference around the five-person cycle
Big hint:
The signed differences must total zero before the five amounts can be summed
Solution:
The signed differences around the cycle have magnitudes 19,19, 7,7, 5,5, 4,4, 1111 and sum 0.0. Thus one side of the sign split must total half of 46,46, namely 23.23. The only split is 19+4=7+5+11.19+4=7+5+11. In one orientation, the amounts are A=E+11,A=E+11, B=E−8,B=E-8, C=E−1,C=E-1, and D=E+4.D=E+4. Their total is 5E+6,5E+6, so 5E+6=565E+6=56 and E=10.E=10. Reversing every sign would give 5E−6=56,5E-6=56, not an integral E.E. Thus Elgin had $10\$10 and E is correct.
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