1995 AMC 12 Problem 22

Attempt Problem 22 of the 1995 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1995 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

A pentagon is formed by cutting a triangular corner from a rectangular piece of paper. The five sides of the pentagon have lengths 13,13, 19,19, 20,20, 2525 and 31,31, although this is not necessarily their order around the pentagon. The area of the pentagon is
459459
600600
680680
720720
745745
Answer: E
Concepts:rectanglesPythagorean theoremarea subtraction
Small hint:
Two pentagon sides are the original rectangle’s full side lengths
Big hint:
Look for two differences among the lengths that form the legs of a right triangle with a third listed length
Solution:
The full rectangle sides must be longer than the two remnants on those same sides. The only assignment whose two differences and remaining cut side form a right triangle is the rectangle 2525 by 31,31, with remnants 2020 and 19.19. The removed corner then has legs 25−20=525-20=5 and 31−19=12,31-19=12, whose hypotenuse is the listed side 13.13. Thus the pentagon’s area is 25⋅31−12(5)(12)=775−30=745. \begin{aligned} 25\cdot31-\frac12(5)(12) &=775-30\\ &=745. \end{aligned} Hence the correct answer is E.
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