1992 AMC 12 Problem 14

Attempt Problem 14 of the 1992 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AMC 12 solutions, or check the answer key.

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14.

Which of the following equations have the same graph? I. y=x−2II. y=x2−4x+2III. (x+2)y=x2−4 \begin{aligned} &\text{I. }y=x-2\\ &\text{II. }y=\dfrac{x^2-4}{x+2}\\ &\text{III. }(x+2)y=x^2-4 \end{aligned}
I\mathrm{I} and II\mathrm{II} only
I\mathrm{I} and III\mathrm{III} only
II\mathrm{II} and III\mathrm{III} only
I,\mathrm{I}, II\mathrm{II} and III\mathrm{III}
None. All the equations have different graphs
Answer: E
Concepts:graphdomain restrictionextraneous component
Small hint:
Pay special attention to what happens when x=−2x=-2
Big hint:
Equation II omits one point, while equation III includes an entire extra vertical line
Solution:
Equation I is the whole line y=x−2.y=x-2. Equation II simplifies to that line only when x≠−2,x\ne-2, so it omits (−2,−4).(-2,-4). In equation III, every point with x=−2x=-2 satisfies 0=0;0=0; for other xx it gives y=x−2.y=x-2. Thus III is the line together with the entire vertical line x=−2.x=-2. The three graphs are different.
Thus the correct answer is E.
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