1991 AMC 12 Problem 3

Attempt Problem 3 of the 1991 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1991 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

(4−1−3−1)−1=\left(4^{-1}-3^{-1}\right)^{-1}=
−12-12
−1-1
112\frac1{12}
11
1212
Answer: A
Concepts:negative exponentreciprocalfraction subtraction
Small hint:
Rewrite the negative first powers as reciprocals
Big hint:
First simplify 14−13\frac14-\frac13, then take its reciprocal
Solution:
We have 4−1−3−1=14−13=−112.4^{-1}-3^{-1}=\frac14-\frac13=-\frac1{12}. Raising this result to the power −1-1 takes its reciprocal, giving −12.-12.
Thus the correct answer is A.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.