1988 AMC 12 Problem 5

Attempt Problem 5 of the 1988 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

If bb and cc are constants and (x+2)(x+b)=x2+cx+6,(x+2)(x+b)=x^2+cx+6, then cc is
−5-5
−3-3
−1-1
33
55
Answer: E
Concepts:polynomial identitiescoefficient comparison
Small hint:
Expand the product on the left
Big hint:
Compare the constant term before comparing the coefficient of xx
Solution:
Expansion gives x2+(b+2)x+2b.x^2+(b+2)x+2b. Thus 2b=6,2b=6, so b=3,b=3, and c=b+2=5.c=b+2=5.
Thus the correct answer is E.
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