1988 AMC 12 Problem 22

Attempt Problem 22 of the 1988 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

For how many integers xx does a triangle with side lengths 10,10, 24,24, and xx have all its angles acute?
44
55
66
77
more than 77
Answer: A
Concepts:acute trianglesPythagorean inequalitiesinteger counting
Small hint:
Apply the strict Pythagorean inequality to the largest side in each possible ordering
Big hint:
The angle opposite 2424 and the angle opposite xx give the restrictive bounds
Solution:
Acuteness requires x2<102+242=676x^2<10^2+24^2=676 and 242<102+x2,24^2<10^2+x^2, so x<26x<26 and x2>476.x^2>476. For integer x,x, this gives 22≤x≤25.22\le x\le25. All four values also satisfy the triangle inequality, so there are 44 values.
Thus the correct answer is A.
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