1965 AMC 12 Problem 31

Attempt Problem 31 of the 1965 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1965 AMC 12 solutions, or check the answer key.

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31.

The number of real values of xx satisfying the equality (logax)(logbx)=logab,(\log_a x)(\log_b x)=\log_a b, where aa and bb are positive constants different from 1,1, is:

00

11

22

an integer greater than 22

not finite

Answer: C
Concepts:logarithmquadraticalgebraic manipulation
Difficulty rating: 2000
Small Hint:

Write every logarithm with natural logs

Big Hint:

The equation reduces to (lnx)2=(lnb)2(\ln x)^2=(\ln b)^2

Solution:

Change of base gives lnxlnalnxlnb=lnblna. \frac{\ln x}{\ln a}\frac{\ln x}{\ln b} =\frac{\ln b}{\ln a}. Since the denominators are nonzero, (lnx)2=(lnb)2.(\ln x)^2=(\ln b)^2. Thus x=bx=b or x=1b.x=\frac{1}{b}. These are distinct because b1,b\ne1, so there are two values.

Therefore, the correct answer is C.

← Problem 30#30
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Problem 31 in Other Years

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