1964 AMC 12 Problem 30

Attempt Problem 30 of the 1964 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1964 AMC 12 solutions, or check the answer key.

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30.

If

(7+43)x2+(2+3)x2=0, \begin{aligned} (7+4\sqrt3)x^2 &+(2+\sqrt3)x\\ &-2=0, \end{aligned}

the larger root minus the smaller root is:

2+33-2+3\sqrt3

232-\sqrt3

6+336+3\sqrt3

6336-3\sqrt3

33+23\sqrt3+2

Answer: D
Concepts:quadraticradicalalgebraic manipulation
Difficulty rating: 1670
Small Hint:

Notice that 7+43=(2+3)27+4\sqrt3=(2+\sqrt3)^2

Big Hint:

For Ax2+Bx+C=0,Ax^2+Bx+C=0, the root difference is B24ACA\frac{\sqrt{B^2-4AC}}{A}

Solution:

Let A=7+43=(2+3)2A=7+4\sqrt3=(2+\sqrt3)^2 and B=2+3.B=2+\sqrt3. The discriminant is B24A(2)=A+8A=9A.B^2-4A(-2)=A+8A=9A. Hence the root difference is 9AA=32+3=633.\frac{\sqrt{9A}}A=\frac3{2+\sqrt3}=6-3\sqrt3.

Therefore, the correct answer is D.

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