1956 AMC 12 Problem 40

Attempt Problem 40 of the 1956 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1956 AMC 12 solutions, or check the answer key.

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40.

If V=gt+V0V=gt+V_0 and S=12gt2+V0t,S=\dfrac12gt^2+V_0t, then tt equals:
2SV+V0\dfrac{2S}{V+V_0}
2SV−V0\dfrac{2S}{V-V_0}
2SV0−V\dfrac{2S}{V_0-V}
2SV\dfrac{2S}{V}
2S−V2S-V
Answer: A
Concepts:kinematics formulasalgebraic eliminationaverage velocity
Small hint:
Use the first equation to replace gtgt in the second
Big hint:
Factor tt after writing gt=V−V0gt=V-V_0
Solution:
From the first equation, gt=V−V0.gt=V-V_0. Therefore S=12(gt)t+V0t=12(V−V0)t+V0t=12(V+V0)t. \begin{aligned} S&=\frac12(gt)t+V_0t\\ &=\frac12(V-V_0)t+V_0t\\ &=\frac12(V+V_0)t. \end{aligned} Solving gives t=2SV+V0.t=\frac{2S}{V+V_0}.
Thus, the correct answer is A.
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