1950 AMC 12 Problem 33

Attempt Problem 33 of the 1950 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1950 AMC 12 solutions, or check the answer key.

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33.

The number of circular pipes with an inside diameter of 11 inch which will carry the same amount of water as a pipe with an inside diameter of 66 inches is:

6π6\pi

66

1212

3636

36π36\pi

Answer: D
Concepts:circle areapower scaling of length, area, and volume
Difficulty rating: 1240
Small Hint:

Water-carrying capacity is proportional to cross-sectional area

Big Hint:

Circular area scales as the square of the diameter

Solution:

The ratio of the diameters is 6:1,6:1, so the ratio of cross-sectional areas is 62:12=36:1. 6^2:1^2=36:1. Thus 3636 of the smaller pipes have the same total cross-sectional area as the larger pipe.

Thus, the correct answer is D.

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