2024 AMC 10A Problem 4

Attempt Problem 4 of the 2024 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

The number 20242024 is written as the sum of not necessarily distinct two-digit numbers. What is the least number of two-digit numbers needed to write this sum?
2020
2121
2222
2323
2424
Answer: B
Concepts:inequalitybounding to limit casesoptimization
Small hint:
The largest two-digit number is 99,99, so kk numbers sum to at most 99k99k
Big hint:
Find the least kk with 99k≥2024,99k \ge 2024, then confirm that many two-digit numbers can reach 20242024
Solution:
Each two-digit number is at most 99,99, so kk of them sum to at most 99k.99k. We need 99k≥2024,99k \ge 2024, which forces k≥20.4,k \ge 20.4, so k≥21.k \ge 21. And 2121 really works: twenty 9999s plus one 4444 give 1980+44=2024.1980 + 44 = 2024. Therefore, the answer is B.
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