2021 AMC 10A Spring Problem 4

Attempt Problem 4 of the 2021 AMC 10A Spring below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10A Spring solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

A cart rolls down a hill, traveling 55 inches the first second and accelerating so that during each successive 11-second time interval, it travels 77 inches more than during the previous 11-second interval. The cart takes 3030 seconds to reach the bottom of the hill. How far, in inches, does it travel?
215215
360360
29922992
31953195
32423242
Answer: D
Concepts:arithmetic sequencesummation
Small hint:
The distances traveled each second form an arithmetic sequence
Big hint:
Find the 3030th term, then use the average of the first and last terms
Video solution:
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Written solution:
The distance travelled every second forms an arithmetic sequence: 5,5+7,5+2⋅7,… 5, 5 + 7, 5 + 2 \cdot 7, \ldots
The standard arithmetic-sequence sum formula is n⋅a1+an2. n\cdot\dfrac{a_1+a_n}{2}. We know the number of terms is 3030 and the first term is 5.5. The last term is 5+29⋅7=208.5 + 29 \cdot 7 = 208.
Plugging these values into the expression yields 30⋅5+2082=15⋅213=3195. 30 \cdot \dfrac{5 + 208}{2} = 15 \cdot 213 = 3195.
Thus, D is the correct answer.
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