2018 AMC 10A Problem 15

Attempt Problem 15 of the 2018 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10A solutions, or check the answer key.

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15.

Two circles of radius 55 are externally tangent to each other and are internally tangent to a circle of radius 1313 at points AA and B,B, as shown in the diagram. The distance ABAB can be written in the form mn,\frac{m}{n}, where mm and nn are relatively prime positive integers. What is m+n?m+n?

2121

2929

5858

6969

9393

Answer: D
Concepts:tangent circlessimilarity
Difficulty rating: 1820
Solution:

Let XX be the center of the large circle and let Y,ZY,Z be the centers of the two smaller circles. Then XY=XZ=135=8XY=XZ=13-5=8 and YZ=10YZ=10.

The radii to tangent points make XAXA collinear with XYXY and XBXB collinear with XZXZ, so XABXYZ\triangle XAB\sim \triangle XYZ. Thus ABYZ=XAXY=138\dfrac{AB}{YZ}=\dfrac{XA}{XY}=\dfrac{13}{8}.

Hence AB=10138=654AB=10\cdot\dfrac{13}{8}=\dfrac{65}{4}, so m+n=65+4=69m+n=65+4=69. Thus, D is the correct answer.

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