2017 AMC 10B Problem 23

Attempt Problem 23 of the 2017 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 10B solutions, or check the answer key.

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23.

Let N=1234567891011124344N=123456789101112\dots4344 be the 7979-digit number that is formed by writing the integers from 11 to 4444 in order, one after the other. What is the remainder when NN is divided by 45?45?

11

44

99

1818

4444

Answer: C
Concepts:modular arithmeticChinese Remainder Theoremdigits
Difficulty rating: 1660
Solution:

To find the remainder when divided by 45,45, we must find the remainder when divided by 55 and 9.9. The remainder when divided by 55 is the remainder when the units digit is divided by 5,5, making it 4.4.

To find the remainder when divided by 9,9, we usually find the sum of the digits. However, each double digit number has the same remainder when divided by 99 as its digit sum, so we can just sum the integers from 11 to 44,44, because each integer is congruent to its own digit sum. This sum is 44452=990,\dfrac{44\cdot45}{2}=990, which is a multiple of 9.9. Thus, NN is a multiple of 9.9.

Since it is a multiple of 99 and has a remainder of 44 when divided by 5,5, the remainder when divided by 4545 is 9.9.

Thus, the correct answer is C .

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