2017 AMC 10A Problem 15

Attempt Problem 15 of the 2017 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 10A solutions, or check the answer key.

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15.

Chloé chooses a real number uniformly at random from the interval [0,2017].[0, 2017].

Independently, Laurent chooses a real number uniformly at random from the interval [0,4034].[0, 4034].

What is the probability that Laurent's number is greater than Chloé's number?

12\dfrac{1}{2}

23\dfrac{2}{3}

34\dfrac{3}{4}

56\dfrac{5}{6}

78\dfrac{7}{8}

Answer: C
Concepts:geometric probabilitysymmetry
Difficulty rating: 1070
Solution:

If Laurent chooses a number in the interval (2017,4034],(2017, 4034], then there is no way that Chloé can have the greater number.

This means that Laurent has a 12\frac{1}{2} chance of automatically winning.

Otherwise, Laurent chooses a number in the interval [0,2017].[0, 2017]. The probability that he gets a greater number than Chloé is the same as Chloé getting a greater number than Laurent.

This means that Laurent has a 12\frac{1}{2} chance of getting a greater number (when working with real intervals, the probability of a tie is essentially 00 due to the infinite size of the intervals).

Laurent's total chance of getting a greater number is 121+1212=34. \dfrac{1}{2} \cdot 1 + \dfrac{1}{2} \cdot \dfrac{1}{2} = \dfrac{3}{4}.

Thus, C is the correct answer.

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