2013 AMC 10B Problem 4

Attempt Problem 4 of the 2013 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

When counting from 33 to 201,201, the number 5353 is in position 51.51. When counting backward from 201201 to 3,3, the number 5353 is in position n.n. What is n?n?
146 146
147 147
148 148
149 149
150 150
Answer: D
Concepts:counting integers in a range
Small hint:
Count backward by using 201201 as position 11
Big hint:
A number xx is in backward position 202−x202-x
Solution:
When counting backward, 201201 is the first number, 200200 is the second, and in general xx is the 202−x202-xth number.
Thus 5353 is the 202−53=149202-53=149th number counted.
Thus, the correct answer is D .
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