2009 AMC 10A Problem 4

Attempt Problem 4 of the 2009 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10A solutions, or check the answer key.

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4.

Eric plans to compete in a triathlon. He can average 22 miles per hour in the 14\tfrac14-mile swim and 66 miles per hour in the 33-mile run. His goal is to finish the triathlon in 22 hours. To accomplish his goal what must his average speed, in miles per hour, be for the 1515-mile bicycle ride?

12011\dfrac{120}{11}

1111

565\dfrac{56}{5}

454\dfrac{45}{4}

1212

Answer: A
Concepts:distance rate and timefraction
Difficulty rating: 1030
Solution:

The swim takes 1/42=18\dfrac{1/4}{2} = \dfrac18 hour and the run takes 36=12\dfrac{3}{6} = \dfrac12 hour. This leaves 21812=1182 - \dfrac18 - \dfrac12 = \dfrac{11}{8} hours for the bicycle ride.

His average speed must be 1511/8=12011\dfrac{15}{11/8} = \dfrac{120}{11} miles per hour.

Thus, the correct answer is A.

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