2006 AMC 10B Problem 4

Attempt Problem 4 of the 2006 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 10B solutions, or check the answer key.

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4.

Circles of diameter 11 inch and 33 inches have the same center. The smaller circle is painted red, and the portion outside the smaller circle and inside the larger circle is painted blue. What is the ratio of the blue-painted area to the red-painted area?

22

33

66

88

99

Answer: D
Concepts:circle areaarea ratio
Difficulty rating: 940
Solution:

The red circle has area π(12)2=π4,\pi(\tfrac12)^2 = \tfrac{\pi}{4}, and the large circle has area π(32)2=9π4.\pi(\tfrac32)^2 = \tfrac{9\pi}{4}. The blue ring is 9π4π4=2π.\tfrac{9\pi}{4}-\tfrac{\pi}{4}=2\pi.

The ratio is 2π÷π4=8.2\pi \div \tfrac{\pi}{4} = 8.

Thus, the correct answer is D.

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