2006 AMC 10A Problem 15

Attempt Problem 15 of the 2006 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 10A solutions, or check the answer key.

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15.

Odell and Kershaw run for 3030 minutes on a circular track. Odell runs clockwise at 250250 m/min and uses the inner lane with a radius of 5050 meters. Kershaw runs counterclockwise at 300300 m/min and uses the outer lane with a radius of 6060 meters, starting on the same radial line as Odell. How many times after the start do they pass each other?

2929

4242

4545

4747

5050

Answer: D
Concepts:relative speeddistance rate and timecircumference
Difficulty rating: 1630
Solution:

Odell's lap is 2π(50)=100π2\pi(50) = 100\pi m at 250250 m/min, taking 100π250=0.4π\frac{100\pi}{250} = 0.4\pi min. Kershaw's lap is 2π(60)=120π2\pi(60) = 120\pi m at 300300 m/min, also 120π300=0.4π\frac{120\pi}{300} = 0.4\pi min.

Their periods are equal. Running in opposite directions, they meet at times t=k2(0.4π)t = \frac{k}{2}(0.4\pi) for k=1,2,k = 1, 2, \ldots Requiring t30t \le 30 gives k600.4π=150π47.7,k \le \frac{60}{0.4\pi} = \frac{150}{\pi} \approx 47.7, so they pass 4747 times.

Thus, the correct answer is D.

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