2003 AMC 10B Problem 22

Attempt Problem 22 of the 2003 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

A clock chimes once at 3030 minutes past each hour and chimes on the hour according to the hour. For example, at 11 PM there is one chime and at noon and midnight there are twelve chimes. Starting at 11:1511{:}15 AM on February 26,26, 2003,2003, on what date will the 20032003rd chime occur?
March 88
March 99
March 1010
March 2020
March 2121
Answer: B
Concepts:date and timesummationprocess simulation
Small hint:
In each 1212-hour period there are 1212 half-hour chimes and 1+2+⋯+12=781+2+\cdots+12=78 hour chimes
Big hint:
A full day has 180180 chimes; count how many occur after 11:1511{:}15 AM on Feb 2626 and accumulate by day
Solution:
Each 1212-hour period has 12+78=9012 + 78 = 90 chimes, so each full day has 180.180.
After 11:1511{:}15 AM on February 26,26, the rest of that day has 9191 chimes. Adding 180180 for each following full day, the count reaches 18911891 by the end of March 8.8.
The remaining chimes fall on March 9:9: the 20032003rd chime is the 112112th chime of that day, occurring at 3:303{:}30 PM on March 9.9.
Thus, the correct answer is B.
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