2003 AMC 10A Problem 21

Attempt Problem 21 of the 2003 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

21.

Pat is to select six cookies from a tray containing only chocolate chip, oatmeal, and peanut butter cookies. There are at least six of each of these three kinds of cookies on the tray. How many different assortments of six cookies can be selected?
2222
2525
2727
2828
729729
Answer: D
Concepts:stars and bars
Small hint:
Count the nonnegative integer solutions to a+b+c=6a + b + c = 6
Big hint:
By stars and bars this is (6+22)\dbinom{6 + 2}{2}
Solution:
An assortment is determined by how many of each type are chosen, so we count nonnegative integer solutions to a+b+c=6.a + b + c = 6.
By stars and bars, placing 22 dividers among 88 slots gives (82)=28\dbinom{8}{2} = 28 assortments.
Thus, the correct answer is D.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.