2002 AMC 10B Problem 21

Attempt Problem 21 of the 2002 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 10B solutions, or check the answer key.

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21.

Andy's lawn has twice as much area as Beth's lawn and three times as much area as Carlos' lawn. Carlos' lawn mower cuts half as fast as Beth's mower and one third as fast as Andy's mower. If they all start to mow their lawns at the same time, who will finish first?

Andy

Beth

Carlos

Andy and Carlos tie for first.

All three tie.

Answer: B
Concepts:rateratio and proportion
Difficulty rating: 1370
Solution:

Let Andy's lawn have area A,A, so Beth's is A2\dfrac{A}{2} and Carlos' is A3.\dfrac{A}{3}. Let Carlos mow at rate R,R, so Beth mows at 2R2R and Andy at 3R.3R.

The times are Andy: A3R,Beth: A/22R=A4R,Carlos: A/3R=A3R. \begin{aligned} &\text{Andy: } \dfrac{A}{3R}, \\ &\text{Beth: } \dfrac{A/2}{2R} = \dfrac{A}{4R}, \\ &\text{Carlos: } \dfrac{A/3}{R} = \dfrac{A}{3R}. \end{aligned}

Since A4R\dfrac{A}{4R} is the smallest, Beth finishes first.

Thus, the correct answer is B.

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