2001 AMC 10 Problem 15

Attempt Problem 15 of the 2001 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 10 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

A street has parallel curbs 4040 feet apart. A crosswalk bounded by two parallel stripes crosses the street at an angle. The length of the curb between the stripes is 1515 feet and each stripe is 5050 feet long. Find the distance, in feet, between the stripes.
99
1010
1212
1515
2525
Answer: C
Concepts:parallelogramarea
Small hint:
The crosswalk is a parallelogram; compute its area using the curb as base
Big hint:
The same area equals stripe length times the distance between the stripes
Solution:
The crosswalk is a parallelogram. Using the curb (1515 ft) as base and the street width (4040 ft) as height, its area is 15⋅40=60015\cdot40=600 square feet.
Using a stripe (5050 ft) as base, the area equals 5050 times the distance dd between the stripes, so d=60050=12.d=\frac{600}{50}=12.
Thus, the correct answer is C.
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