2018 AMC 8 第 9 题

先试着解答 2018 AMC 8 第 9 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2018 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

9.

Tyler 正在给他 1212 英尺乘 1616 英尺的客厅铺地砖。他计划沿房间边缘用一英尺乘一英尺的正方形地砖铺一圈边框,其余部分用二英尺乘二英尺的正方形地砖铺满。他一共会用多少块地砖?
Tyler is tiling the floor of his 1212 foot by 1616 foot living room. He plans to place one-foot by one-foot square tiles to form a border along the edges of the room and to fill in the rest of the floor with two-foot by two-foot square tiles. How many tiles will he use?
4848
8787
9191
9696
120120
答案:B
知识点:铺砖面积
小提示:
先数 11 英尺宽边框上的地砖,注意角落不要重复计算
Count the 11-foot border tiles first, being careful not to double-count the corners.
大提示:
去掉一圈 11 英尺边框后,剩余矩形是 1010 英尺乘 1414 英尺
After removing a 11-foot border, the remaining rectangle is 1010 feet by 1414 feet.
视频讲解:
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文字解答:
注意边框每平方英尺需要一块地砖,所以四边相加会得到 16+12+16+12=5616+12+16+12=56 块。不过这样四个角各重复计算了一次,所以要减去 44。因此边框共需要 56−4=5256-4=52 块 1×11\times 1 正方形地砖。
由于每边都去掉了一英尺宽的边框,剩下的内部矩形为 1010 英尺乘 1414 英尺。它要完全铺上 2×22 \times 2 的地砖,所以这部分需要 10⋅142⋅2=35 \dfrac{10\cdot14}{2\cdot2} = 35 块地砖。
边框需要 5252 块 1×11\times 1 地砖,内部需要 3535 块 2×22\times 2 地砖,因此一共需要 52+35=8752+35=87 块地砖。
所以正确答案是 B。
Note that each square foot of the border would require one tile, meaning that the border will take 16+12+16+12=5616+12+16+12=56 tiles. However, notice that this will cause overlapping tiles in each of the four corners, so to fix this, we subtract 4.4. Therefore, the border will take 56−4=5256-4=52 1×11\times 1 square tiles to completely tile.
Since we have removed one foot from each side due to the border, the remaining rectangle is 1010 feet by 1414 feet. This must be tiled completely by 2×22 \times 2 tiles, so it will take 10⋅142⋅2=35 \dfrac{10\cdot14}{2\cdot2} = 35 tiles in total to tile this area.
As it takes 5252 1×11\times 1 square tiles to tile the border, and 3535 2×22\times 2 square tiles to tile the remaining area, it will take 52+35=8752+35=87 tiles in total to fill in Tyler’s entire living room floor.
Thus, the correct answer is B.
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