2014 AMC 8 第 2 题
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所有题目均经美国数学协会（MAA）官方合法授权使用。
2.
Paul 欠 Paula 美分，并且口袋里有 美分、 美分和 美分硬币可用来付钱。他可以用来支付的硬币数最大值与最小值之差是多少？
Paul owes Paula cents and has a pocket full of -cent coins, -cent coins, and -cent coins that he can use to pay her. What is the difference between the largest and the smallest number of coins he can use to pay her?
小提示：
用最小的硬币可以使硬币数量最大
Use the smallest coins to maximize the number of coins.
大提示：
用一枚二十五美分和一枚十美分硬币可以使硬币数量最小
Use a quarter and a dime to minimize the number of coins.
解答：
要使用最多硬币，Paul 可以全用 美分硬币，得到 枚。
要使用最少硬币，他可以用一枚 美分和一枚 美分硬币，共 枚。差为 。
所以正确答案是 E。
To use the largest number of coins, Paul would use only -cent coins, which gives coins.
To use the smallest number of coins, Paul would use a -cent coin and a -cent coin, for a total of coins. The difference is .
Thus, E is the correct answer.
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